I would really appreciate any help with this. If I were capable of applying an upward force at ( 0, 0, -0.25 ), wouldn't the box start spinning away ( into the page ) from me - and not spin clockwise? Team Z 79-04 Mustang WELDED Lower Torque Box Replacement Kit 329.00 Add to Cart Rock Solid Motorsports 1979-2004 Mustang Tubular Front End Kit Foxbody SN95 - Rock Solid Motorsports RSM 661.99 Choose Options Team Z Motorsports sku: TZM-TFEW-79-93 Team Z Foxbody Mustang 79-93 Tubular Front End Kit - Welded 945. If I were holding that box in my hand, then ( 0, 0, -0.25 ) would be on the side facing me. And the crossproduct is, so the torque is in the $x$ direction and the box should rotate clockwise? Where P value is the pressure specified in the Pressure value box and t end is. To find the torque, we would applyĪnd so $r$ is and $F$ is. The Force/Torque PropertyManager applies forces, moments, or torques with. The $x$ axis is left(-) and right(+), the $y$ axis is up(+) and down(-), and the $z$ axis is into(+) and out of(-) the page.Ī force is applied at the point ( 0, 0, -0.25 ). I have a box that's centered at ( 0, 0, 0 ) with length ( $x$ dimension ) = 1, width ( $y$ dimension ) = 0.25, and height ( $z$ dimension ) = 0.5. I think I'm missing something with torques.
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